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picture in comments help??? solution related question
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\[|17x|>-17\]This means: \[-17x > -17 ~ ~ \text{or}~ ~ 17x> -17\]
When dividing or multiplying by a negative, the sign flips.
?
can you solve for \[-17x > -17 ~ ~ \text{or}~ ~ 17x> -17\]
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not really
Divide by -17 and flip the sign. \[x < \frac{-17}{-17} ~ \text{or}~ x > \frac{-17}{17}\]
Now just solve for your inequality.
haha if i knew how to do it i would but this still makes no sense
um, is an absolute value ever less than zero?
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