the area of a rectangle is 99yd^2 and the length is 7yd then double the widtth
question is real unclear what does "the length is 7 yds then double the width" mean?
can you post a screenshot or something? hard to guess what is means
y yards more than twice the width?
thats all it says thats why it confused me. I dont understand what I am supposed to be doing.
can you post a picture? or write it again verbatim? the question is really unclear
my guess: the area of a rectangle is 99 square yards the length is 7 more than twice the width find the dimensions but that is just a guess
omg im an idiot your right. I didnt read the whole thing correctly. I hate online clases
ok now we are getting somewhere lets call the width \(x\) so the length is \(2x+7\)
since area is length times width you have \[x(2x+7)=99\] solve for \(x\)
i.e. \[2x^2+7x-99=0\] if you are lucky it factors
is it 11??
man my algebra stinks
it should be \[x(2x+7)=99\ 2x^2+14x=--\\ 2x^2+14x-99=0\]
mine too lol I havent been in school in 8 years so I had to take college algebra
no that is not good either
if it is an on line class can you post a screen shot?
how do i screen shot my laptop?
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