If y varies directly as x, find the constant of variation if y = 12 when x = 1/3.
The possible answers are... A: 36 B: 4 C: 6 D: 12
direct variation is made by the formula of y=kx plug that in, solve for k.
So technically, it's 12 = 36/4/6/12 * 1/3?
i don't really know what you mean but 12=k(1/3) what times 1/3 =12
What I meant was that I put 12 as Y, times K, which could be either 36, 4, 6 or 12, multiplied by 1/3. Is that what I do? Or do I do something else?
i think you are making is harder than it has to be 12=k(1/3) whatever answer choice you have satisfies k that makes that ^ equation true, is your constant.
which means there is only one answer
Oh, okay. So I divide 12 by 1/3?
yes, that would work.
Okay, give me a minute or so.
np
I got 4. But I don't think that's right.
if your dividing by less than 1, the number always turns out greater than the original number
check that you put parenthesis.
So it should be different, I'll try again.
Wait, is this a flip and multiply thing? Because if it is then the answer should be 36.
correct.
So 36 is the answer by the calculations we did?
yep
Okay, just to check, Y = 12, x = 1/3, then that becomes 12/1 * 3/1, which becomes 36/1 and thus 36, am I correct?
yes
That's good, I'll wait to see what triciaal has to say first, though.
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