Question

write a function of the form y=f(x) that satisfies the conditions:
holes at 3=-1 and x=0 resembles y=x^2

What the heck???

so far i got x(x-3) / x(x-3)

Answer 1

uh so you need holes at 3 and -1 yes?

Answer 2

or also at zero?

Answer 3

i think point (3,-1) is the hole. the question is exactly how it is written

Answer 4

well, the phrasing on the 3=-1 makes no sense to me. That is what I am trying to understand

Answer 5

i think it's x(x-3)+9 / x(x-3)-x^2

but i dont know if it resembles y=x^2

Answer 6

but you have the right idea

Answer 7

same, it was written like that on the wksheet

Answer 8

maybe a type-o and it should be x=-1?

Answer 9

that would make more sense

Answer 10

so let's see, we need it to cancel out and leave us x^2 on top only ya?

Answer 11

we need it to go haywire at x=-1 and x=0

Answer 12

BUT, the limit at these points must equal x^2 evaluated at those points

Answer 13

you are on the right track, give it a try using x=-1 and x=0 as your haywire points