please help me fan and medal
Solve for x: -3|x - 3| = -6 x = 1, x = -1 x = 1, x = 5 x = 0, x = 5 No solutions
@amistre64 @acxbox22 @andrewhaze @ayyookyndall @Awolflover1 @sleepyjess @danniisnotcool
Okay since x-3 is an absolute value, it means the number can be a positive or a negative as long as the difference is the same value. What multiplied -3 = -6?
@Nnesha @nincompoop @nobrainiachere
what u mean
An absolute value is the number of spaces from the integer to 0, so basically you remove the negative. Like if you have |-2|, it's the same as just saying 2.
To simplify the equation a bit use this: |x - 3| = 2 what two numbers could you use for x now?
5
And what else?
ummm
If |2| = 2 and |-2| = 2, then what would be the second x?
1
Yes! So which answer choice has both x = 5 and x = 1?
b
Yep. :) Do you understand it a bit more or do you still need help?
thank u so much
No problem. :)
Choose the correct description of the graph of the compound inequality: x - 3 < -9 or x + 5 greater than or equal to 12 A number line with a closed circle on -6, shading to the left, and an open circle on 7, shading to the right A number line with an open circle on -6, a closed circle on 7, and shading in between A number line with an open circle on -6, shading to the left, and a closed circle on 7, shading to the right A number line with a closed circle on -6, an open circle on 7, and shading in between
@danniisnotcool
Okay, think of the two inequalities as equations, x - 3 = 9 x + 5 = 12 Solve for x on both then put the original sign back in.
@josedavid
sorry about that
yes
Look at what I said above the mention
A=12 B=17
u there
@danniisnotcool
Yes, sorry was doing homework myself. So which kind of circle would < get on a number line?
cool no rush
what u mean
is the first one
Would the point on a number line be a filled in circle or an open circle for a <?
is c is hard
Oh, and for the second equation, it's x is greater than or equal to 7, not 17.
But yes, the answer is c.
thank u so much thank u
u are the best i need to go bye take care
i got it right
Join our real-time social learning platform and learn together with your friends!