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Mathematics 18 Online
OpenStudy (anonymous):

which of the binomials below is a factor of this trionomial ? x^2+13x+42 a. x-7 b. x^2+12 c. x+84 d. x+ 7

OpenStudy (ashes.boom):

well because the first term is x^2 you know that the factored binomial cant be b

OpenStudy (ashes.boom):

right?

OpenStudy (anonymous):

I want to say its c but im not really sure where to begin at ever finding the answer :l

OpenStudy (ashes.boom):

okay so you start by finding factors of +42 that sum 13 okay?

OpenStudy (ashes.boom):

when you are factoring trinomials you take the first term's coefficient and multiply it by the last term's coefficient but becuase the first coefficent is a 1 you get 1 * 42 which is 42

OpenStudy (ashes.boom):

you have to find the pair of factors of the two coefficents you multiplied together that will equal the middle term coefficent when you add or subtract. Does that make sense?

OpenStudy (anonymous):

so find 2 number that 13?

OpenStudy (ashes.boom):

yes

OpenStudy (ashes.boom):

list factors of 42

OpenStudy (ashes.boom):

1 and 42 2 and 21 3 and 14 6 and 7

OpenStudy (ashes.boom):

which ones equal 13?

OpenStudy (ashes.boom):

6 and 7 right?

OpenStudy (ashes.boom):

so then you can split the middle term into two different terms like this: x^2 + 6x + 7x + 42

OpenStudy (ashes.boom):

then you can factor by grouping: grouping two terms at a time and finding the greatest common factor between the two

OpenStudy (ashes.boom):

for the first two: x^2 and 6x, the only thing they have in common is an x so you divide both of the terms by x. x^2/x = x 6x/x = +6 write it like this: x(x + 6)

OpenStudy (ashes.boom):

same for the last two: 7x + 42 --> the only thing they have in common is a 7 so divide by 7 7x/7 = x 42/7= + 6 write it like this: x(x + 6)

OpenStudy (ashes.boom):

when you factor by grouping you ave to make sure that the two binomials in the parentheses (in this case the x+6) match. if they dont match check your math.

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