Question

Help please:
In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?

Answer 1

It is a permutation.and I know the equation is nPr = n!/(n-r)!

Answer 2

Hey, someone on here asked this question! Look here for answer and such :) http://openstudy.com/study#/updates/53641144e4b0fac5fcff4d01

Answer 3

Oh okay thanks! I'll go look at it!

Answer 4

Tell me how it goes if you can :)

Answer 5

The answer seems to be 2.7....etc. But, doesn't that seem off a little?

Answer 6

how many choices for the first seat?

Answer 7

Are you given the choices?

Answer 8

No no choices.

Answer 9

Hm. I mean even if you copy and pasted your question into google. People have done this. And it is permutation. ..I am unsure as well.

Answer 10

I appreciate your help and yeah I lack the common sense side. But, I'm going to try and contact my teacher! Thanks again though. Have a blessed day.

Answer 11

how many choices for the first seat?

Answer 12

Sorry I couldn't help much! You as well :)

Answer 13

60 kids, you can choose any of them to sit there right?

Answer 14

pick one, there are 59 choices for the 2nd seat, pick 1
there are 58 choices for the 3rd seat, pick 1
there are 57 choices for the 5rd seat, pick 1

etc ...

this results in 60 ways to pick 59 ways to pick 58 ways to pick 57 ways to pick ....

or simply: 60*59*58*57*.... for 10 spots ..

Answer 15

60! = 60*59*58*57*56*...*3*2*1

if we divide that by (60-10) = 50, so 50!

60.59.58.57.56.55.54.53.52.51.50!
-------------------------------
50!

501/501 cancel leaving us with ....

60.59.58.57.56.55.54.53.52.51 this big old product

Answer 16

*** 50!/50!

Answer 17

so, we can either do the long version, or if we have a calculator with the C and P options or a (!) option ...

60 P 10 is entered, or 60!/50!

Answer 18

I contacted my teacher and she said that 2.74 x 10 ^17 is correct.

Answer 19

Thanks for your help too amistre64!