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Factor completely 3+27x
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@conqueror
I need help with this problem and I don't get the substitution of the 0x
HINT: \(27x = 3\cdot9x\)
You can factor \(3\) out.
So do you divide 3
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@geerky42 is the 3 the GCF and then you 3+0x+27x
Yeah, GCF of 3 and 27x is 3. So you can factor 3 out; \[3+27x\quad\Longrightarrow \quad3(1+9x)\]
That as far as you can go.
oh my gosh you are a lifesaver! a invisible light bulb just came on from this thanks so much
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