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Mathematics 9 Online
OpenStudy (anonymous):

Factor completely 3+27x

OpenStudy (anonymous):

@conqueror

OpenStudy (anonymous):

I need help with this problem and I don't get the substitution of the 0x

geerky42 (geerky42):

HINT: \(27x = 3\cdot9x\)

geerky42 (geerky42):

You can factor \(3\) out.

OpenStudy (anonymous):

So do you divide 3

OpenStudy (anonymous):

@geerky42 is the 3 the GCF and then you 3+0x+27x

geerky42 (geerky42):

Yeah, GCF of 3 and 27x is 3. So you can factor 3 out; \[3+27x\quad\Longrightarrow \quad3(1+9x)\]

geerky42 (geerky42):

That as far as you can go.

OpenStudy (anonymous):

oh my gosh you are a lifesaver! a invisible light bulb just came on from this thanks so much

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