Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Solve for x

OpenStudy (anonymous):

\[\sqrt{2x+3} = \sqrt{6x-1}\]

TheSmartOne (thesmartone):

Square both sides and tell me what you get.

OpenStudy (anonymous):

2x+1=6x-1 1=4x-1 0=4x - 2 ?

OpenStudy (anonymous):

then you factor 4 i believe ?

TheSmartOne (thesmartone):

It is 2x+3 not 2x+1

TheSmartOne (thesmartone):

So solve from here again: 2x+3=6x-1

OpenStudy (anonymous):

oh so , 2x +3 = 6x- 1 3= 4x - 1 0= 4x - 4 x= 1 ?

TheSmartOne (thesmartone):

correct :)

OpenStudy (anonymous):

thanks so much

OpenStudy (anonymous):

could you help me on another?

TheSmartOne (thesmartone):

And jus to make sure that is correct, we could plug it in: \(\sf\Large\sqrt{2x+3}=\sqrt{6x-1}\) \(\sf\Large\sqrt{2(1)+3}=\sqrt{6(1)-1}\) \(\sf\Large\sqrt{2+3}=\sqrt{6-1}\) \(\sf\Large\sqrt{5}=\sqrt{5}\)

TheSmartOne (thesmartone):

And sure, make a new post and tag me. I'll be right there. :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!