Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day. Write your equation below. My birthday is June 8, 1999. How do i do dis ? ;p
@sleepyjess
@chosenmatt
gimme a sec ;)
ok thank you ^-^
u know....i rather get someone else too help u because i don't wanna give u false information because im not 100% sure sorry :(
its okay.. who do you think can help me ? ;p
@perl @adrynicoleb @dan815 @Trinity_haha @inowalst @iGreen
@js7474 please help :)
@TheSmartOne please help
Sorry hun i have no clue O.o
Vertex form is \(\sf a(x-h)^2+k\)
yay i got someone too help u :)
The 'a' should be kept 1 as it is way easier than choosing another value between -4 and 4.
'k' is 8 which is the day in your birthday.
And 'h' is 6 because June is the 6th month.
@chosenmatt Thank you so much !
@TheSmartOne sooo it would be f(x) = 1(x - 6)^2 + 8
right ?
Correct :)
ok... how do i turn that equation in standard form ?
Standard Form is \(\sf Ax^2+By=C\)
So expand \(\sf (x-6)^2\) and combine it with the 8 and you can also think of \(\sf f(x) = y\) and get it into that format above.
:-)
(x - 6)(x - 6) ?
I get x^2 - 12x + 44
@TheSmartOne
so y = x^2 - 12x + 44
Now move around the terms so it is in the format of \(\sf Ax^2+By=C\)
umm.. x^2 + 44 - 12x = y ?
Correct. Ignore what I was saying lol. Good job :) What is the next part?
so it is like that ? ok lol ;p how do i graph it now.
@iambatman explains it nicely over here too: http://openstudy.com/study#/updates/53af97e9e4b02c45b016004b
Thank you so much :D
Anytime :)
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