@Michele_laino What is the surface area of the figure? http://static.k12.com/calms_media/media/243500_244000/243747/1/7428d4bb911e93e97cd24196dbab100e55ec21cd/VHS_PA_S2_05_L313_UT_Q12_b.gif A. 300 cm2 B. 390 cm2 C. 195 cm2 D. 220 cm2
here the lateral area A, is given by the subsequent computation: \[\large A = 2 \times \left( {5 \times 6 + 5 \times 6 + 5 \times 6 + 5 \times 6 + 10 \times 6 + 10 \times 6} \right) = ...?\]
since we have to sum the area of each lateral surface, of our prism
480
@Michele_Laino
@Michele_Laino
sorry, I have made an error, it is: \[A = 5 \times 6 + 5 \times 6 + 5 \times 6 + 5 \times 6 + 10 \times 6 + 10 \times 6 = 240\;c{m^2}\]
is the answer D?
no, since we have four surface of 30 cm^2 area each, and two surface of 60 cm^2 each, then in total we have a laterl surface of:30*4+2*60=240 cm^2
so B?
I think it is no one of them, since the area is 240 cm^2
please check your options
they are the right ones
I can assure that my computation is right
another way to get your answer is this: the perimeter of the lateral surface P is: \[P = 5 + 5 + 5 + 5 + 10 + 10 = 40\;cm\] so the lateral area A is: \[A = P \times 6 = 40 \times 6 = 240\;c{m^2}\]
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