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Mathematics 22 Online
OpenStudy (anonymous):

an arrow is fired straight up into the air from ground level. after t seconds its altitude is s(t)=-16t^2+100t where s(t) is given in feet: after how many seconds will the arrow be 100 feet above ground

OpenStudy (solomonzelman):

above the ground, or below the ground ?

OpenStudy (solomonzelman):

it begins (going up) above the ground, and if you say "will" - it will be BELOW the ground (not above it).

OpenStudy (solomonzelman):

are you sure you didn't allow any typos in your post ? maybe you have a correction to make?

OpenStudy (anonymous):

no thats what the question says.

OpenStudy (solomonzelman):

well it is above the ground right after t=0

OpenStudy (solomonzelman):

it will be above the ground as somewhere after 6, -16t^2 exceeds the 100t in absolute value.

OpenStudy (solomonzelman):

I can't help it if the question is wrong.

OpenStudy (solomonzelman):

here is the graph, so that you can see. Just went on desmos.com to do it. https://www.desmos.com/calculator/xgtovnks83

OpenStudy (anonymous):

okay thank you for tryimg

OpenStudy (solomonzelman):

you can see that after t=6.25 it will be below the ground

OpenStudy (solomonzelman):

bye, and good luck-:(

OpenStudy (anonymous):

yes i see thank you Ill ask my teacher about it

OpenStudy (solomonzelman):

alrighty then... see you!

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