an arrow is fired straight up into the air from ground level. after t seconds its altitude is s(t)=-16t^2+100t where s(t) is given in feet: after how many seconds will the arrow be 100 feet above ground
above the ground, or below the ground ?
it begins (going up) above the ground, and if you say "will" - it will be BELOW the ground (not above it).
are you sure you didn't allow any typos in your post ? maybe you have a correction to make?
no thats what the question says.
well it is above the ground right after t=0
it will be above the ground as somewhere after 6, -16t^2 exceeds the 100t in absolute value.
I can't help it if the question is wrong.
here is the graph, so that you can see. Just went on desmos.com to do it. https://www.desmos.com/calculator/xgtovnks83
okay thank you for tryimg
you can see that after t=6.25 it will be below the ground
bye, and good luck-:(
yes i see thank you Ill ask my teacher about it
alrighty then... see you!
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