Question

r^2/3+r^1/3-12=0

Answer 1

hint: \(\large \bf {
r^{\frac{2}{3}}+r^{\frac{1}{3}}-12=0\implies r^{\frac{1}{3}\cdot 2}+r^{\frac{1}{3}}-12=0
\\ \quad \\
(r^{\frac{1}{3}})^2+r^{\frac{1}{3}}-12=0
}\)

Answer 2

so... either factor it, or use the quadratic formula, either way will do

Answer 3

how would you factor it

Answer 4

treat r^(1/3) as x. so this will give you x^2 + x - 12 = 0. now factor that

Answer 5

(x+4) and (x-3)?

Answer 6

yep, no replace the x with r^(1/3) again

Answer 7

and that should be your answer