Question

Section: Frequency:
M 21
A 26
T 25
H 28


compare the theoretical probability to the experimental probability of landing on H.
@perl @Music_me @bibby @jigglypuff314

Answer 1

Please help :( anyone?

Answer 2

I know the experimental is 7/25 but I don't know theoritical...

Answer 3

So, there r 100 in total when u add all of'em up, so 100 would be the denominator. There r 4 letters, so 100 divided by 4 is 25: 25/100.
Now, u simplify that.

Answer 4

no. It says it is a spinner with four equal size sections marked m a t h

Answer 5

Music_me can't be simplified.

Answer 6

o wait it can

Answer 7

But is that correct? I tried that but I thought it was wrong

Answer 8

Well, what did u get when u simplified?

Answer 9

4/25

Answer 10

since each letter is theoretically equally likely, you should have 1 in 4 chance for H

Answer 11

yea and thats 25/100 so you simplify it

Answer 12

No it's not 4/25

Answer 13

I get it.. but I have one more question

Answer 14

5/25 music_me

Answer 15

which is 1/5

Answer 16

No. 25/100 simplified is actually 1/4 bcz 100 divided by 25 is 4 & 25 divided by 25 is 1

Answer 17

Manny rolls a number cube labeled 1 through 6 and spins a spinner with four equal sections, labeled 1,2,3,4 if both numbers are odd, he wins. Otherwise, Gabriel wins. Use a list to find the sample space. then find the probability that gabriel wins

Answer 18

Can u help me with that ^?

Answer 19

Sure

Answer 20

2 parts to the question...

Answer 21

So, let's fist do the list

Answer 22

There r 6 sides to the number cube & 4 sections to the spinner. Now, there will b 24 combinations in the list & I will only give u the first 4 u name the rest ok?

Answer 23

ok?

Answer 24

1, 1; 1, 2; 1, 3; 1, 4

Answer 25

?

Answer 26

Ok so, the list is practically just combinations. Like the ones I gave. 1, 1; 1, 2; 1, 3; 1, 4; 2, 1; 2, 2; 2, 3; 2, 4

Answer 27

I did 5 odd in a spinner and a cube so I added the outcomes up got 5/10 and 1/2... which is wrong... :/?

Answer 28

im confused..

Answer 29

oh wait we have to make a list of like 1;1 1;2 1;3 1;4 1;5 1;6
2;1 2;3 2;4 all the way to 6 and see which is odd??

Answer 30

yes or no?

Answer 31

Yes

Answer 32

Ok so wait

Answer 33

1;1 1;2 1;3 1;4 1;5 1;6 2;1 2;2 2;3 2;4 2;5 2;6 3;1 3;2 3;3 3;4 3;5 3;6 4;1 4;2 4;3 4;4 4;5 4;6 5;1 5;2 5;3 5;4 5;5 5;6 6;1 6;2 6;3 6;4 6;5 6;6
Now count which are odd? thats my answer??

Answer 34

No, the total for the odd has to do more with finding the probability

Answer 35

so what do I do with this list??

Answer 36

Remember I told u that there were 24 combinations in the list. Well, that is the denominator fir the ftraction

Answer 37

oh so its 18/24 which is reduced to 6/8 which then reduces to 3/4 is that my answer?

Answer 38

Yes correct! :)

Answer 39

Thanks

Answer 40

YW