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Mathematics 21 Online
OpenStudy (josedavid):

please help me some one

OpenStudy (josedavid):

Choose the slope-intercept equation of the line that passes through the point (-2, 2) and is parallel to y = 4x + 7. y = 4x + 10 y = one fourthx + 5 halves y = -4x - 6 y = -one fourthx + 3 halves

OpenStudy (josedavid):

The first four terms of a sequence are shown below: 6, 2, -2, -6 Which of the following functions best defines this sequence? f(1) = 6, f(n + 1) = f(n) + 4; for n ≥ 1 f(1) = 6, f(n + 1) = f(n) - 2; for n ≥ 1 f(1) = 6, f(n + 1) = f(n) - 4; for n ≥ 1 f(1) = 6, f(n + 1) = f(n) + 2; for n ≥ 1

OpenStudy (josedavid):

Which of the following equations best represents the line segment PQ? y = -3x + 2 y = -2x + 1 y = -3x - 2 y = -2x - 1

OpenStudy (ashes.boom):

a line is parallel with another line if they have the same slope but different y intercept

OpenStudy (ashes.boom):

so for the first question its a

OpenStudy (josedavid):

okay thanks

OpenStudy (josedavid):

and the second one

OpenStudy (ashes.boom):

idk about the second one lol but the one after that, only one of them has the correct y intercept so find the equation that shows the y intercept that matches the graph

OpenStudy (josedavid):

so u are saying the 3

OpenStudy (ashes.boom):

no not the third choice the y intercept on the graph shows +1

OpenStudy (josedavid):

ohhh okay the first one

OpenStudy (ashes.boom):

technically the second one becuase the last part of the equation, the last term, is the y intercept

OpenStudy (ashes.boom):

y = -2x + 1 is the answer

OpenStudy (josedavid):

are u sure

OpenStudy (ashes.boom):

looking at the graph you can see taht the line intersects the y axis at the point +1 so the only equation that shows the y intercept at +1 is the second one also the slope is a -2 and you can see how the line goes down and to the right matching the slope so yes im sure

OpenStudy (josedavid):

okay thank u so much

OpenStudy (ashes.boom):

no problem :) sorry i couldnt help you with the second one tho good luck on that one

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