slope -6 through (-7,7) the equation of the line is?
slope intercept form is y = mx +b where m is slope and b is y-intercept so replace m by -6 and x y by order pair (x,y) then solve for b
You can use point slope form y-y1=m(x-x1) to solve this as well
\(\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({\color{red}{ -7}}\quad ,&{\color{blue}{ 7}})\quad % (c,d) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= -6 \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
would this be (-6,0)
what would be the equation of the line?
y=6x+14 I think
(-6 , 0) is what ?? equation should be in this form y = mx +b
y=-6x+0
it is y=-6x-35
|dw:1428791400469:dw| replace x y and m by their values |dw:1428791475661:dw| so yes that's right :)
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