Question

Subtract and simplify: (14x2 + 8) – (6x2 + 5x – 1) so u know the 2 is a square
a. 8x2 – 5x – 6
b. 8x2 + 5x + 9
c. 8x2 – 5x + 9
d. 20x2 + 5x – 6

Answer 1

what do you think @Takirap2000

Answer 2

i don't know i ain't good at this kind of math

Answer 3

I have 6 more question to ask because i ain't good at it.

Answer 4

ok first we apply the distributive property
\[14x^{2}+8-(6x ^{2})-(5x)-1(-1)\]
then we simplify
\[14x ^{2}+8-6x ^{2}-5x+1\]

Answer 5

okay

Answer 6

so we add 14x2 + 6x2 + (-5x) - 8 + 1

Answer 7

Then we move -6x2
\[14x ^{2}-6x ^{2}+8-5x+1\]
then subtract 6x2 from 14x2 to get 8x2
\[8x ^{2}+8-5x+1\]

Answer 8

whats next

Answer 9

we flip the 8 and 5x over

Answer 10

show me

Answer 11

the we will get 8x2 + 5x + 9

Answer 12

nope try again remember when flipping it stays the same

Answer 13

+okay so to 8x2 + (-5x) 8 + 1

Answer 14

no look

We move 8
\[8x^{2}-5x+8+1\]
then whats next @Takirap2000

Answer 15

which will be 8x2 - 5x + 9 that the answer

Answer 16

correct :D

Answer 17

okay I got 6 more question