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Mathematics 9 Online
OpenStudy (anonymous):

Graph and identify the asymptotes. y=(1)/(x+3)+4

OpenStudy (anonymous):

MISTAKE IT'S SUPPOSED TO BE -4 NOT +

OpenStudy (anonymous):

Will medal + best answer for correct graph and asymptotes.

OpenStudy (anonymous):

x+3 can't equal zero, so when your function is `f(x)=1/(x+3)` your vertical asymptote is?

OpenStudy (anonymous):

(and +4 at the end is just a vertical shift)

OpenStudy (anonymous):

OK sorry didn't see your answer here let mee look...

OpenStudy (anonymous):

y?

OpenStudy (anonymous):

NO WAIT THAT STUPED is it 1?

OpenStudy (anonymous):

if x + 3 = 0 then x = ?

OpenStudy (anonymous):

-3?

OpenStudy (anonymous):

x=-3

OpenStudy (anonymous):

@fbi2015 x = -3?

OpenStudy (anonymous):

yes, so the asymptote is x=-3

OpenStudy (anonymous):

But the graph?

OpenStudy (anonymous):

I had to depart for a minuite, excuse me for that.

OpenStudy (anonymous):

|dw:1428866759900:dw|

OpenStudy (anonymous):

well, the graph of /x looks like this|dw:1428866820478:dw|

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