Question

Can we use constant acceleration equations on spring problems?

a) no, because a is proportional to x
b) yes, because F is proportional to x
c) yes, because we have a constant, k, in Hooke’s Law
d) no, because the period is not the same

Answer 1

Im thinking its D

Answer 2

no, you cannot.

with a spring, F is proportional to x because Hooke's Law tells us that F = kx. thus, a is proportional to x, as F = ma.

all of which means that a = kx, and NOT a = "some constant".

Answer 3

oh ok thanks so much!