FAN AND MEDAL Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats. What is the theoretical probability that the family has two dogs or two cats? Describe how to use two coins to simulate which two pets the family has.
yes you can use 2 coins to simulate this the possible results from tossing 2 coins together is HH, HT TH and HH or if you like DD, DC , CD or CC for cats and dogs. and the theoretical probability of each is 1/4 since these 4 are all equally likely . So what do you think the theoretical probability of 2 dogs or 2 cats is? i
P(DD) = 1/4 , P(CC) = 1/4
P(CC or DD) = ?
or you can look at it another way - DD and CC are 2 out of the 4 possible outcomes so ?
HOLD ON thers a mistake there the order of cat and dog does not matter so there are 3 possibilities DD, DC and CC making the theoretical property of each of these = 1/3 so P(DD or CC) = ?
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