Question

Find the limit when n approaches infinity of cos^2 (n) / 2^n

Answer 1

I think we have to use Squeeze theorem here... I'm not sure how.

Answer 2

For all values of \(n\),\[0\le\cos^2n\le1\]
So
\[\lim_{n\to\infty}0\le\lim_{n\to\infty}\frac{\cos^2n}{2^n}\le\lim_{n\to\infty}2^{-n}\]

Answer 3

Oh of course, thank you

Answer 4

yw