this is the next question but i can't put anymore in the blue box its making it eeor
Express the perimeter of the triangle as a polynomial.
Reply Using Drawing
A.–11x – 5
B. 11x – 4
C. 10x – 5
D. 11x + 4
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jagr2713 (jagr2713):
is there a picture
OpenStudy (anonymous):
yes but i can't get it up it in the other question
jagr2713 (jagr2713):
what are the numbers
OpenStudy (anonymous):
4x + 1 left side x - 7 right side
6x + 2 bottom
jagr2713 (jagr2713):
Ok so we add them together
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OpenStudy (triciaal):
the perimeter is the sum of the lengths all around the figure
for a triangle there are 3 lengths to add
OpenStudy (anonymous):
10x - 3
jagr2713 (jagr2713):
First we move
\[4x+x+1-7+6x+2\]
Then we add 4x and x to get 5x
\[5x+1-7+6x+2\]
jagr2713 (jagr2713):
Then we move 6x
\[5x+6x+1-7+2\]
and then we add 5x and 6x to get 11x
\[11x+1-7+2\]
jagr2713 (jagr2713):
Whats next @Takirap2000
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OpenStudy (anonymous):
(5x + 6x) + (1 - 7) + 2
OpenStudy (anonymous):
11x - 6 + 2
11x - 4
jagr2713 (jagr2713):
Correct :D
OpenStudy (triciaal):
so correct is option B
OpenStudy (triciaal):
the above is correct
just a note: because of the commutative property for addition it does not matter how you add the like terms and it saves time if you do the computation in one step
all the x together and all the numbers together
so x(6 + 4 + 1) + (1 + 2 -7) = 11 x - 4
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