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What is the probability of winning a lottery in which you must choose 6 numbers from the numbers 1 through 13? a) Assuming that order is unimportant. b) Assuming order is important.
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The formula for combinations (how to choose r things from a larger set of n things) is:
So for part "a" we have 13! / 6!*(7!) = 13* 12* 11* 10* 9 * 8* 7! / 6!*7! = 13* 12* 11* 10* 9 * 8 / 6 * 5 * 4 * 3 * 2 = 13* 11* 2 * 3 * 2 = 1,716 and to check that, here's a combination calculator: http://www.1728.org/combinat.htm
should we assume duplication is not acceptable?
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