Question

3) WILL BE GIVING MEDAL AND FAN!!!

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Answer 1

D

Answer 2

You need to work on reducing the numbers and simplifying the variables.

Answer 3

but is D right?

Answer 4

To reduce the number part,

\(\dfrac{\color{red}{4}x^8}{\color{red}{16}x^2}\)

Answer 5

Yes, D is correct.

Answer 6

To reduce the number part, you need to find the largest number that divides evenly into 4 and 16.
That number is 4, so:

\(=\dfrac{\cancel{\color{red}{4}}x^8}{\cancel{\color{red}{4}}\times 4x^2}\)

\(=\dfrac{x^8}{4x^2} = \dfrac{x^{8 - 2}}{4} = \dfrac{x^6}{4} \)