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Use a graph of the function to explain the geometric meaning of the value of the integral.
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@Michele_Laino
\[\int\limits_{0}^{3} (x ^{3}-6x) dx\]
thats the integral
we have to draw the graph of the function x^3-6x
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here is my screenshot:
the x-intercepts of that function, are: x^3-6x=0 what is x?
\[\Large \begin{gathered} {x^3} - 6x = 0 \hfill \\ x\left( {{x^2} - 6} \right) = 0 \hfill \\ \end{gathered} \]
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