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If √9x +5=7, what is the value of x? Pleasee Medal and Fan :)
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\[\sqrt{9x}+5=7\]
subtract both sides by 5 and we have \(\sqrt{9x}=2\), right?
How to get rid of square root? Do you know?
No :/ unless i divide both sides by 3x? Im not sure
square root is inverse of square, right? \(2^2=4, \sqrt{4}=2\) \(3^2=9, \sqrt{9}=3\) \(4^2=16, \sqrt{16}=4\) \(\vdots\)
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So squaring it will cancel square root and leave us with \(9x\), right?
since we squared \(\sqrt{9x}\), we must also square 2 So we now have \(9x = 4\) Makes sense so far?
x = 4/9
that is the next step and also the answer
hope this helps :)
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