Question

WHAT IS THE DOMAIN OF THE FUNCTION?
y=3sqrt 6x+42

Answer 1

for which values of x the function doesn't exist?

Answer 2

6X

Answer 3

i think

Answer 4

idk but thats what the q says

Answer 5

the 6x can't be negative because the square root from negative number doesn't exist

Answer 6

so 6x=0 or 6x>0
x=0 or x>0

Answer 7

okay well can u help me with another one

Answer 8

yes

Answer 9

thanks!!

Answer 10

What are the domain an range of the functions y=2 sqrt 3x+4-5

Answer 11

include the brackets

Answer 12

is 3x+4 under the radical symbol>

Answer 13

yes

Answer 14

y=2 sqrt [3x+4-5]

Answer 15

\[y=3\sqrt {6x+42}\] like this or
\[y=3\sqrt {6x}+42\]

Answer 16

first one

Answer 17

you cannot take the square root of a negative number(unless its complex)

Answer 18

therefore
6x+42>0
x>-42/6
x>-7

Answer 19

0 is fine too so
x>=-7

Answer 20

wait which answer is that for?

Answer 21

you tell me

Answer 22

lol is it for the second one
yall confusing me

Answer 23

domain means all the possible value of x, where the function wont break apart

Answer 24

@dan815
i need help with the other one i put up

Answer 25

What are the domain an range of the functions y=2 sqrt 3x+4-5

Answer 26

but you still didnt get question 1

Answer 27

i did

Answer 28

i been did i had moved on

Answer 29

... whats the answer?

Answer 30

it was -7

Answer 31

i just need number 2

Answer 32

What are the domain an range of the functions y=2 sqrt 3x+4-5

Answer 33

Okay, so do the same thing you did in question 1 on number 2 now

Answer 34

i did but i came up with some thing thats not on my answer choices

Answer 35

\[y=2 \sqrt {3x+4}-5\] I think it should be like this

Answer 36

yeass

Answer 37

thats what it looks like

Answer 38

okay so the stuff under the square root has be more than - again

Answer 39

so what is x?

Answer 40

3

Answer 41

has be more than 0

Answer 42

yes

Answer 43

when x is 3 what is under the square root?

Answer 44

um.....................idk