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Mathematics 7 Online
OpenStudy (anonymous):

Check my answer? Four polynomial functions are shown below: f(x) = x^3 + 3x^2 - 4x - 12 g(x) = x^3 - 3x - 2 p(x) = x^2 + 3x + 2 t(x) = x^2 + x - 2 Which of the following functions has 1 and -2 as its zeros? f(x) g(x) p(x) t(x)

OpenStudy (anonymous):

1 think its g(x) but 1'm not sure.

OpenStudy (anonymous):

@SolomonZelman @freckles

hero (hero):

If you think g(x) is the correct function, then g(1) and g(-2) must both equal zero.

hero (hero):

Do you know how to find g(1) and g(-2)?

OpenStudy (anonymous):

1 think so...

OpenStudy (anonymous):

you just input 1 or -2 for x right?

OpenStudy (anonymous):

both g(1) and g(-2) are -4, if 1 did that correctly.

hero (hero):

You can program the functions into your calculator and then check that way if you have a TI calc.

OpenStudy (anonymous):

1 have a T1 calculator but 1'm not sure how to do that. By T1 you mean Texas 1nstument right?

hero (hero):

Yes. If you don't have a TI-Nspire, then you'll have to find your calc guidebook in order to figure out how to program functions into your calc. I only know how to do it for TI-Nspire series.

hero (hero):

But g(1) and g(-2) are both -4 so g(x) is not the right function.

OpenStudy (anonymous):

Oh

hero (hero):

Now that you know how to do this, you should be able to use the same approach to find the correct function.

OpenStudy (anonymous):

1 know its not f(x)...

hero (hero):

We can definitely eliminate p(x) because p(1) won't work to find zero.

hero (hero):

This we can figure out by observation since adding positive numbers will never yield zero.

OpenStudy (anonymous):

ohhh its t(x)

OpenStudy (anonymous):

sorry I didn't even see that one.

hero (hero):

The correct answer is t(x) and you could have also figured it out by observation as well. Great job.

OpenStudy (anonymous):

Thanks so much!

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