Check my answer? Four polynomial functions are shown below: f(x) = x^3 + 3x^2 - 4x - 12 g(x) = x^3 - 3x - 2 p(x) = x^2 + 3x + 2 t(x) = x^2 + x - 2 Which of the following functions has 1 and -2 as its zeros? f(x) g(x) p(x) t(x)
1 think its g(x) but 1'm not sure.
@SolomonZelman @freckles
If you think g(x) is the correct function, then g(1) and g(-2) must both equal zero.
Do you know how to find g(1) and g(-2)?
1 think so...
you just input 1 or -2 for x right?
both g(1) and g(-2) are -4, if 1 did that correctly.
You can program the functions into your calculator and then check that way if you have a TI calc.
1 have a T1 calculator but 1'm not sure how to do that. By T1 you mean Texas 1nstument right?
Yes. If you don't have a TI-Nspire, then you'll have to find your calc guidebook in order to figure out how to program functions into your calc. I only know how to do it for TI-Nspire series.
But g(1) and g(-2) are both -4 so g(x) is not the right function.
Oh
Now that you know how to do this, you should be able to use the same approach to find the correct function.
1 know its not f(x)...
We can definitely eliminate p(x) because p(1) won't work to find zero.
This we can figure out by observation since adding positive numbers will never yield zero.
ohhh its t(x)
sorry I didn't even see that one.
The correct answer is t(x) and you could have also figured it out by observation as well. Great job.
Thanks so much!
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