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Mathematics 18 Online
OpenStudy (anonymous):

In the triangle below, calculate the sec J.

OpenStudy (anonymous):

|dw:1429055181265:dw|

OpenStudy (dtan5457):

secant is the opposite of cos cos=adj/hyp sec=hyp/adj

OpenStudy (dtan5457):

so from angle J, identify your adj side and hypotenuse

OpenStudy (anonymous):

I think that the adjacent side is g and the hypotenuse is h.

OpenStudy (dtan5457):

correct

OpenStudy (jdoe0001):

hmmm that triangle has missing units there but as dtan5457 said, use SOH CAH TOA \(\bf sin(\theta)=\cfrac{1}{csc(\theta)} \qquad % cosine cos(\theta)=\cfrac{1}{sec(\theta)} \qquad % tangent tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)} \)

OpenStudy (jdoe0001):

hmmm actually, I meant to post \(\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad % cosine cos(\theta)=\cfrac{adjacent}{hypotenuse} \qquad % tangent tan(\theta)=\cfrac{opposite}{adjacent}\) anyhow

OpenStudy (anonymous):

Thank you, both of you! (^_^) I think that I understand it now.

OpenStudy (jdoe0001):

yw

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