In the triangle below, calculate the sec J.
|dw:1429055181265:dw|
secant is the opposite of cos cos=adj/hyp sec=hyp/adj
so from angle J, identify your adj side and hypotenuse
I think that the adjacent side is g and the hypotenuse is h.
correct
hmmm that triangle has missing units there but as dtan5457 said, use SOH CAH TOA \(\bf sin(\theta)=\cfrac{1}{csc(\theta)} \qquad % cosine cos(\theta)=\cfrac{1}{sec(\theta)} \qquad % tangent tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)} \)
hmmm actually, I meant to post \(\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad % cosine cos(\theta)=\cfrac{adjacent}{hypotenuse} \qquad % tangent tan(\theta)=\cfrac{opposite}{adjacent}\) anyhow
Thank you, both of you! (^_^) I think that I understand it now.
yw
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