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for number 1 its radical 2
for number #2 I think each equation has 2 solutions
Can you please show me how you got the first one? thank you !
plug in radical 2 for y and solve for x then once you find x value then check your work by multiplying the x value and radical 2 which is the y value
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if you get 4 then the answer is right
in the second one \(y^2=x+4\) so you have \[x^2+x+4=4\] and you can solve that i believe there are two solutions
thank you so much!!
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