Question

What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)?

x= –y2/16+6y/16–41/16

y= –x2/16+6x/16–41/16

y=x2/16–6x/16+41/16

x=y^2/16–6y/16+41/16

Answer 1

\[x=-\frac{ -y^2 }{ 16 }+\frac{ 6y }{ 16}-\frac{ 41 }{ 16 } \]

Answer 2

Thats how a is set up

Answer 3

@Michele_Laino

Answer 4

@perl

Answer 5

@zepdrix

Answer 6

@Nnesha

Answer 7

the ones with x2 and y2 should be y^2 and x^2