If astronaut A(90kg) and astronaut B(110kg) are linked by 9.5m of rope and the centre of mass is 5.2m from astronaut A. What is the velocity of the 2 astronauts?
Rope was originally 15m long but astronaut A reeled it in on her end by 5.5m in 8.5sec. Not sure if this is important or not Thanks in advance guys
so they would be moving towards each other at a velocity of 5.5/8.5 m/sec
this motion will be centred on the centre of mass: because there is no external force, so no change in momentum of overall system. initially A was 110*15/200 = 8.25 from CoM. now she is 5.225 (the 5.3 in the question is inaccurate). she has moved 3.05m in 8.5s. she started at zero so her velocity, **assuming** constant force and acceleration, is given by (1/2)(vf + 0) * 8.5 = 3.05 ditto for B
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