Ask your own question, for FREE!
Physics 16 Online
OpenStudy (anonymous):

If astronaut A(90kg) and astronaut B(110kg) are linked by 9.5m of rope and the centre of mass is 5.2m from astronaut A. What is the velocity of the 2 astronauts?

OpenStudy (anonymous):

Rope was originally 15m long but astronaut A reeled it in on her end by 5.5m in 8.5sec. Not sure if this is important or not Thanks in advance guys

OpenStudy (alekos):

so they would be moving towards each other at a velocity of 5.5/8.5 m/sec

OpenStudy (irishboy123):

this motion will be centred on the centre of mass: because there is no external force, so no change in momentum of overall system. initially A was 110*15/200 = 8.25 from CoM. now she is 5.225 (the 5.3 in the question is inaccurate). she has moved 3.05m in 8.5s. she started at zero so her velocity, **assuming** constant force and acceleration, is given by (1/2)(vf + 0) * 8.5 = 3.05 ditto for B

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!