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Find the zeros of the following polynomial.

P(x) = 5x^2 + 22x + 8

a. x = 2/5 ; x = 4
b. x = -2/5 ; x = -4
c. x = -2/5 ; x = 4
d. x = 2/5 ; x = -4

Question

Will give medal and fan to
anyone that helps!

Find the zeros of the following polynomial.

P(x) = 5x^2 + 22x + 8

a. x = 2/5 ; x = 4
b. x = -2/5 ; x = -4
c. x = -2/5 ; x = 4
d. x = 2/5 ; x = -4

dan815 · Answer

Hi there!
 What have you tried so far?

anonymous · Answer

im not sure where to start ):

dan815 · Answer

P(x) = 5x^2 + 22x + 8
We are trying to find the x values that make this function 0 so,
0= 5x^2 + 22x + 8
Now you can use the quadratic formula or solve this by first putting them in factored form 

0 = 5x^2 + 22x + 8
   =(ax+b)(cx+d)
you have to figure out what a,b,c,d, are so that multiplication of these 2 brackets gives back the expression you started with