Mathematics
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OpenStudy (jaybear97):
Geometry help!!
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OpenStudy (jaybear97):
OpenStudy (anonymous):
area of a circle = pi r^2
sector = theta (in rad) *r^2
OpenStudy (anonymous):
=30*pi/180 * 12^2
OpenStudy (jaybear97):
24 pi?
OpenStudy (jaybear97):
or 75.36
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OpenStudy (anonymous):
24 pi
OpenStudy (jaybear97):
thanks! could you help me with a few more?
OpenStudy (anonymous):
ok
OpenStudy (jaybear97):
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OpenStudy (anonymous):
circle is pi r^2
sector is theta (rad) r^2
pi r^2-theta(rad) r^2
r^2(theta(rad)=pi)
OpenStudy (anonymous):
r=16/2
45*pi/180=1/4pi
8^2(pi-1/4pi)=64pi(1-1/4)
OpenStudy (anonymous):
3/4*64 pi= 48 pi
OpenStudy (jaybear97):
so its 48?
OpenStudy (anonymous):
48 pi
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OpenStudy (jaybear97):
OpenStudy (jaybear97):
I only have 2 more after this one.
OpenStudy (anonymous):
look at it. is 1/4 of a circle okay
OpenStudy (anonymous):
and tringle
OpenStudy (anonymous):
so finding the area of 1/4 circle then subtract the triangle
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OpenStudy (anonymous):
(1/4 pi 8^2)-1/2 *8^2
OpenStudy (anonymous):
8^2(1/4pi-1/2)
8^2(pi/4-2/4)=8^2(pi-2)/4
OpenStudy (anonymous):
=18.24
OpenStudy (jaybear97):
OpenStudy (jaybear97):
@acxbox22
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OpenStudy (anonymous):
the area of a circle - 1/4 of a circle + triangle
OpenStudy (anonymous):
the area of a circle = pi r^2, r=18
area of 1/4 a circle =pi r^2/4
area of the triangle = 1/2 b*h = 1/2 18*18
OpenStudy (anonymous):
=pi *18^2-pi* 18^2/4+ 1/218^2
OpenStudy (anonymous):
=3/4*pi*18^2+1/2*18^2
OpenStudy (anonymous):
925