Question

Factorise completely x^2+x-12

Answer 1

Factoring x2+x-12

The first term is, x2 its coefficient is 1 .
The middle term is, +x its coefficient is 1 .
The last term, "the constant", is -12

Step-1 : Multiply the coefficient of the first term by the constant 1 • -12 = -12

Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is 1 .
Try doing step 2.

Answer 2

Okay.

Answer 3

I'll do 2 and you do the other 2,
-12 + 1 = -11
-6 + 2 = -4

Answer 4

I don't understand whats goingon lol

Answer 5

Ok fine here,
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is 1 .

-12 + 1 = -11
-6 + 2 = -4
-4 + 3 = -1
-3 + 4 = 1 That's it

Answer 6

However you have to do this,
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 4

Answer 7

Is there a way u can explain it without the mathematical terms becoz it confuses me lol

Answer 8

Not really. I like to explain it mathematically it is my part you know?

Answer 9

Try this.
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 4
x2 - 3x + 4x - 12

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-3)
Add up the last 2 terms, pulling out common factors :
4 • (x-3)
Step-5 : Add up the four terms of step 4 :

Answer 10

(2x-3)(4x-3) ?????????

Answer 11

No it would be (x + 4) (x - 3)

Answer 12

(x + 4) * (x - 3)

Answer 13

See how i got that?

Answer 14

not really

Answer 15

Well look over the steps :).

Answer 16

k

Answer 17

Well i need to help someone else, hope i helped you out!