pls help me i will metal
George measured the capacity of a cardboard box as 400 in3. The true capacity of the cardboard box is 450 in3.
What is the percent error in George’s measurement? If necessary, round to the nearest percent.
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OpenStudy (anonymous):
@Softballgirl_09 @Turquoisnowflake pls help me
OpenStudy (anonymous):
Ok I,m reading one sec
OpenStudy (anonymous):
X is the name for percent of error
So....
OpenStudy (anonymous):
Does this help? @baytotheocean
OpenStudy (anonymous):
\(*o*)/
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OpenStudy (anonymous):
one more @Turquoisnowflake
OpenStudy (anonymous):
Before beginning a fundraiser, Lindsey estimated that the fundraiser would earn $500. She sold 114 raffle tickets at $5 each for the fundraiser, actually earning for the fundraiser.
What was the percent error in Lindsey’s estimate? Round to the nearest tenth of a percent, if necessary.
A.
12.3%
B.
14%
C.
70%
D.
77.2%
OpenStudy (anonymous):
i think its b
OpenStudy (anonymous):
......Reading.......
OpenStudy (anonymous):
I've got it one sec
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OpenStudy (anonymous):
Here it is.....
OpenStudy (anonymous):
The answer would be B. 14%
Take 570 - 500 = 70
Do 70/500 * (100) to get percentage
So we get 0.14 * 100 = 14% which is B.