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Mathematics 13 Online
OpenStudy (anonymous):

surface area question ? http://bit.ly/1PwEOeK

OpenStudy (anonymous):

As you can see in the figure, there are 2 right-angled triangles and 3 rectangles. I believe you can see them.

OpenStudy (anonymous):

Cannot you?

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

The total surface area is sum of the areas of all geometric figures. The area for triangle is base*height/2, or 8*6/2=24in^2. Since we have 2 of these, so we double this area, being 24*2=48in^2 As for the rectangle at the bottom, the formula to use is length*breadth or 8*20=160in^2. For the other rectangles, their breadth will be the hypotenuse of the right-angled triangles, which are found by Pithagoras Theorem h=sqrt(side1^2 + side2^2) or sqrt( 8^2+6^2)=10in^2. Since we have 2 of these rectangles, we double it. being 10*2=20in^2 Finally we sum all the areas. What do you get?

OpenStudy (anonymous):

are you from africa? nice profile pic by the way lol

OpenStudy (anonymous):

@Hoslos

OpenStudy (anonymous):

Yes, I am. haha, How did you come up with that?

OpenStudy (anonymous):

@emily753159 ?

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