surface area question ? http://bit.ly/1PwEOeK
As you can see in the figure, there are 2 right-angled triangles and 3 rectangles. I believe you can see them.
Cannot you?
@dan815
The total surface area is sum of the areas of all geometric figures. The area for triangle is base*height/2, or 8*6/2=24in^2. Since we have 2 of these, so we double this area, being 24*2=48in^2 As for the rectangle at the bottom, the formula to use is length*breadth or 8*20=160in^2. For the other rectangles, their breadth will be the hypotenuse of the right-angled triangles, which are found by Pithagoras Theorem h=sqrt(side1^2 + side2^2) or sqrt( 8^2+6^2)=10in^2. Since we have 2 of these rectangles, we double it. being 10*2=20in^2 Finally we sum all the areas. What do you get?
are you from africa? nice profile pic by the way lol
@Hoslos
Yes, I am. haha, How did you come up with that?
@emily753159 ?
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