Can someone guide me through finding sin 105 degrees using the half angle formula?
This is what I have so far. 210 degrees \[\pm \sqrt{\frac{ 1-\frac{ \sqrt{3} }{ 2 } }{ 2 }}\]
so far so good?
yes because you have subbed into a half angle formula for sinx/2
then next step, i should just to cancel some denominators by multipying each term by 2?
I would get rid of the fraction in the top of the fraction first by multiplying top and bottom by 2 then trying to bring stuff out of the root
hmmm try 210 = 180 + 30 and then apply sin(A+B) = sinAcosB + cosAsinB...
that is addition formula not half angle formula is it not?
anyway carry on, since you have done it correctly assuming that cos(105)=root3/2
so leave the denominator alone for now, and just multiply the top part by 2/2?
\[\frac{ 1-\frac{ \sqrt{3} }{ 2} }{ 2 }= \frac{ 2(1)- \frac{ 2\sqrt{3} }{ 2 } }{2(2) }\]
then obviously put your square root back
after that step you are pretty much finished to be honest
im getting \[\frac{ \sqrt{2-\sqrt{3}} }{ 2 }\]
is my answer correct?
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