help please? Medal & Fan I am not looking for the answer to anything, I just need someone to help me learn how to find the volume of solid figures. (p.s. idk what 'volume' is eiter)
nvm XD
ok volume of wat
of a cone
\[\pi r^2 h/3\]
:P
\[\pi \] =3.14
okay, so I have this math problem. A cone is inscribed in a regular square pyramid. If the pyramid has a base edge of 6" and a slant height of 9", find the volume of the cone. how would I use this information to fill out that formula. sorry, i am really bad at math. i need like a full talk through, if u can give me one
\[r^2\] = half the length of the bottom circle squared
wait for like 5 minutes
k :)
O_O my bro has the same question for his homework ima copy and paste XD
area of the cone will equal 1/3 (area of the base) (height) for the area of the base, we know that the cone has a diameter of 6" (since it is the largest possible circle inside the square base). so use the area of a circle formula to get: (pi)r^2 where r=3 (1/2 of 6) 9(pi) the height is a little tickier, since you know the slant height, you need to use the properties of a right triangle to get the height. The hypotenuse is 9" and the base is 3" so we use a^2 + b^2 = c^2 3^2 + b^2= 9^2 9+b^2=81 b^2=72 b=8.49 now that you have the height and the area of the base, put it all together to get: 1/3 (9(pi))(8.49) your answer is 25.47 in^3
okay, how you did it makes sense to me, but the choices are 12sqrt 2pie 18sqrt 2pie 27pie
well that would be easier
u still there?
ya :c im confused
b
thnx but can you explain how u got it? :P
nvm i gov up kill me
@xapproachesinfinity help meh bro
lol k thanks tho XD have a good night :)
@xapproachesinfinity u there???
@perl could u help?
@rational
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