Question

WILL MEDAL :) Solve for d in the following equation: c(ad)+x=bd+ad(yz)
A) d= ca-b-ayz
B) d= -x/ (ca-b-ayz)
C) d= x/a(c-b-yz)
D) d=bd-x/c-yz

Answer 1

thats what the other answers look like

Answer 2

First you divide both sides by d then you will get sth like this :
\[ac + \frac{ x }{ d } = b+ayz\]
then get the term (ac) from the left hand side to the write hand one then you will get :
\[\frac{ x }{ d } = b+ayz - ac = -(ac -ayz-b)\]
by taking inverse of both sides :
\[\frac{ d }{ x } = \frac{ -1 }{ ac - ayz - b }\]
Then multiply by x, you simply get d

\[d = \frac{ -x }{ ac - b - ayz }\]

Let me know if you got :)

Answer 3

Thank you! :)