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Mathematics 15 Online
OpenStudy (anonymous):

Verify the Identity: cot θ ∙ sec θ = csc θ

OpenStudy (anonymous):

@iambatman

OpenStudy (irishboy123):

re-write in terms of sine and cosine and it should be clear

OpenStudy (anonymous):

can someone walk me through it

OpenStudy (lυἶცἶ0210):

Like Irish boy said, rewrite them: \(\Huge \frac{\cos\theta}{\sin\theta}*\frac{1}{\cos\theta}=\frac{1}{\sin\theta} \)

OpenStudy (lυἶცἶ0210):

Notice anything that can cancel?

OpenStudy (anonymous):

i got 1/tan(θ)*1/cos(θ)=csc(θ)

OpenStudy (anonymous):

@lυἶცἶ0210

OpenStudy (lυἶცἶ0210):

Why did you rewrite it like that?

OpenStudy (anonymous):

i replaced the left side to try to make it equal to the right

OpenStudy (lυἶცἶ0210):

Well you're right on that. But changing it to sines and cosines is usually easier.

OpenStudy (anonymous):

how do i do that

OpenStudy (lυἶცἶ0210):

Well cotanget can be seen as the reciprocal of tanget in terms of sine and cosine. So when \(\large \tan\theta=\frac{a}{b} \) that means \(\large \cot\theta=\frac{b}{a} \) So \(\Large tan\theta=\frac{sin\theta}{cos\theta} \) , just reciprocate that \(\Large cot\theta=\frac{cos\theta}{sin\theta} \) like I showed you earier.

OpenStudy (lυἶცἶ0210):

You got the \(\sec\theta\) right as \(\large \frac{1}{cos\theta}\)

OpenStudy (lυἶცἶ0210):

Just cross-cancel now and the answer will reveal itself

OpenStudy (anonymous):

ok thank you

OpenStudy (lυἶცἶ0210):

Hmmm, you're welcomee, if you have any more questions don't hesitate to ask! Good luck \(\Huge \color{green}\star^{\color{red}{\star^{\color{blue}{\star}}}} \)

OpenStudy (anonymous):

so from cos(θ)/sin(θ)*1/cos(θ)=csc(θ) i cancel cos(θ) with it self @lυἶცἶ0210

OpenStudy (anonymous):

@CGGURUMANJUNATH can you help me finish this please lυἶცἶ0210 went offline

OpenStudy (anonymous):

@butterflydreamer @Godlovesme @IrishBoy123

OpenStudy (anonymous):

irish is that last part i said right is that what i do

OpenStudy (anonymous):

butter fly i believe i cancel cos(θ) with its self so my final answer is 1/Sin θ = csc θ

OpenStudy (butterflydreamer):

that is correct. |dw:1429352255879:dw|

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