find x in the triangle??
i know that the area is 12.
can you set it up for me?
my bad, it's just a pythagorean theorem problem
\[ (6m)^2+(4m)^2 = x^2 \]
for some reason i don't think i'm doing this correctly.
a^2+b+2=c^2 in right triangles where a, b are the legs and c is the hypotenuse
but with m in the equation im not understanding ho to solve it
I'm pretty sure the m just means meters
if not, then treat it as you would anything \((6m)^2+(4m)^2=x^2\\x=\sqrt{(6m)^2+(4m)^2}\) also if it isn't meters, than your answer to area should have an m
oh so i can take the m out and solve.
so 52 m^2 ?
yeah, and since \(x=\sqrt{52m^2}=\sqrt{52}\sqrt{m^2}\), you can simplify it like that.
but it could also remain as 52m^2 ?
that's kinda pointless given that we have to simplify the radical
sorry im confused then
can you help me simplify it?
just do it without the m's, you get the same answer. \(6^2+4^2=x^2\)
yeah that would still give me 52m^2 then. after that what am i supposed to do with it to simplify?
how? there are no m's there, where are you getting m's from?
i thought i just add it on ? okay so 52^2
then what?
wut
\(x^2=6^2+4^2\\x^2=36+16\\\x^2=52\)
you said it needed to be simplified further. is 52^2 my answer? that's what i've been asking.
tkae the square root of both sides to solve for x. 52^2 makes absolutely no sense. show your work so I can understand where you're getting the number from
|dw:1429401090657:dw|
x is an unknown, you can't just replace it with a number. we're solving for x, remember? 36+16=x^2 to solve for x take the square root of both sides.
what do mean? |dw:1429401306637:dw|
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