Question

what is the general form of the equation of a circle with its center at(-2, 1) and passing through (-4,1)

Answer 1

well the general form is

\[(x - h)^2 + (y - k)^2 = r^2\]

where (h, k) is the centre and r is the radius

Answer 2

substitute the centre values....

then substitute the point x = -4 and y = 1

to calculate r^2

and then you have the equation