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The function f(x) = 6x^2 + 1 is defined over the interval [–2, 5]. If the interval is divided into n equal parts, what is the width of each interval, Δx? 5/n 6/n 7/n 8/n
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@alexray19
hey!
hello!
So start by figuring out how wide the interval is...
As in the function's domain, [-2, 5]. How wide is that?
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for example if I divide your interval by 2, I get: |dw:1429422315677:dw| since the middle point is: (5-2)/2=3/2 so each subset is: 5-3/2=3/2-(-2)=7/2 wide
a length of 7
yea
so its c?
It is C
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yes! that's right!
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