Question

Compute the value of the discriminant and give the number of real solutions of the quadratic equation.

Answer 1

-3x^2+x-1=0

Answer 2

for a quadratic:\[ax^2+bx+c=0\]
the discriminate is: \(b^2-4ac\)

Answer 3

The discriminant of a quadratic is \[b^{2}-4ac\]
Here, a is -3, b is 1, and c is -1

Answer 4

I got -11 for discriminant and 0 for real solution. Is that correct?

Answer 5

If the discriminant is zero: there is one solution (or two equal solutions)

if the discriminant is positive: there are two real solutions.

if the discriminant is negative: there are no real solutions (two complex solutions )

Answer 6

okay thankyou