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In triangle ABC, what is the measure of angle C if A = 100°, a = 125, and c = 10? 4.52° 8° 12.31° Angle C does not exist; no triangle can be formed.
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Use the laws of sin sinA/a=sinC/c
*sine
remember when your looking for an angle, you have to use sin^-1
so how am I going to set the formula up?
\[\frac{ \sin100 }{ 125 }=\frac{ sinC }{ 10 }\]
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use a calculator and solve for sin C
so its 12.31
no you forgot to plug in sin^-1
sin^-1(sin100(10)/(125)=angle c
yup I knew it 4.519
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good job
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