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In triangle ABC, what is the length of side b if B = 10°, C = 135°, and c = 45? 3.24 3.33 3.82 11.05
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apply law of sins: sinC/c = sinB/b
I set it up like this and got http://www.wolframalpha.com/input/?i=sin^-1%28sin135%2810%29%2F%2845
Yeah, looks the right way.
it looks the right way but..
You got me confused too.\[b = \frac {\sin{\beta} \times c}{\sin{\gamma}}\]
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you know what I have no idea no more
The law says that the ratio between lenght and sin of the opposed angle is the same for all three sides / angles.
im brain dead now
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