Mathematics
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OpenStudy (dtan5457):
Solve for sin a/2 when cos a=4/5 , o
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OpenStudy (dtan5457):
just to check i got
\[\frac{ 3\sqrt{10} }{ 10 }\]
OpenStudy (dtan5457):
correct?
OpenStudy (dtan5457):
and wouldn't cos/2 be the same thing?
OpenStudy (welshfella):
I guess you would use the identity cos a = 1 - 2 sin^2 (a/2) ?
OpenStudy (welshfella):
how did you get the 3?
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OpenStudy (dtan5457):
I just used the half angle formula
OpenStudy (welshfella):
oh - i cant remember that one lol
OpenStudy (welshfella):
I got sqrt10/10 using my formula. Again its a while since I did trig....
OpenStudy (dtan5457):
@Nnesha
OpenStudy (welshfella):
cosa = 1 - 2 sin^2 (a/2)
4/5 = 1 - 2 * 10/100
4/5 = 1 - 1/5
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OpenStudy (welshfella):
so it does fit
OpenStudy (dtan5457):
ohhh, your saying that the answer is sqrt of 1/10?
OpenStudy (dtan5457):
if so , I see what i did wrong, i'm suppose to subtract not add 5+4
OpenStudy (dtan5457):
so cos/2 would be \[\frac{ 3\sqrt{10} }{ 10 }\]
sin/2=\[\sqrt{\frac{ 1 }{ 10 }}\]
OpenStudy (dtan5457):
@welshfella
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OpenStudy (welshfella):
yes
OpenStudy (dtan5457):
so both those are correct?
OpenStudy (welshfella):
yes
OpenStudy (dtan5457):
now i need to solve for tan /2
OpenStudy (dtan5457):
im actually getting just 1/3
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OpenStudy (welshfella):
oh - now i definitely cant remember the tan/2 formula , i'm afraid
OpenStudy (dtan5457):
OpenStudy (dtan5457):
looks a lot easier actually
OpenStudy (dtan5457):
im just getting
(3/5)/1+4/5=1/3
OpenStudy (welshfella):
yea - they are vaguely familiar lol
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OpenStudy (dtan5457):
are you able to do it?
OpenStudy (dtan5457):
@TheSmartOne
OpenStudy (welshfella):
yes 1/3 is correct
OpenStudy (dtan5457):
ok ty