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Mathematics 14 Online
OpenStudy (anonymous):

A player tosses three coins. He wins $3 if 3 tails occur. $2 if 2 tails occur. $1 if 1 tail occur and loses if 0 tail occur. Adjust the cost of game to make it fair. Find theoretical mean and variance.

OpenStudy (anonymous):

Help please

OpenStudy (anonymous):

i have calculated a bit

OpenStudy (anonymous):

|dw:1429506371371:dw|

OpenStudy (anonymous):

how do i make the game fair what on earth is that?

OpenStudy (anonymous):

where is everyone help please!!

OpenStudy (anonymous):

Note, the game would be fair if it costs $1 to play.

OpenStudy (wolf1728):

How did you determine that $1 per play is fair?

OpenStudy (anonymous):

it says in a similar question in my notes wait let me post it

OpenStudy (wolf1728):

Because $1 per player would definitely favor the player.

OpenStudy (wolf1728):

I mean $1 per PLAY

OpenStudy (anonymous):

how do i make the game fair the average should equal zero when summed

OpenStudy (wolf1728):

I'm working on that. I'm looking up the game of Chuck-A-Luck on Wikipedia. It works with 3 dice (as opposed to 3 coins).

OpenStudy (anonymous):

OpenStudy (anonymous):

these are my notes where it is shown what is fair and what isnt

OpenStudy (anonymous):

and i have to make a question myself and adjust it to fair. so i created this one

OpenStudy (wolf1728):

So, am I right in thinking that the winning probabilities add up to 12/8?

OpenStudy (anonymous):

i dont know about this

OpenStudy (anonymous):

can u tell me how did u think winning prob. adds to 12/8

OpenStudy (wolf1728):

I looked at column Xp (X=x) 3rd column over

OpenStudy (anonymous):

the column which i draw adds to 1, the third one

OpenStudy (wolf1728):

I was only adding up the positive numbers. Okay, adding all four, it adds to 1 Maybe it should add to zero to be a fair game? So, should each play cost $12?

OpenStudy (anonymous):

yea it should add zero to be fair

OpenStudy (anonymous):

*add to zero

OpenStudy (wolf1728):

1 out of 8 times you win $3 plus the bet 2 out of 8 times you win $2 plus the bet 3 out of 8 times you win $1 plus the bet.

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

this is a project i got and i have to create a game, these are the things it says 1. Calculate the probabilities of winning at least three different amounts of money and the probability of losing the game 2. Decide on how much you will charge to play the game and the amount each player will gain/lose for each outcome 3. By using the probabilities, calculate the expected gain/loss per game and the theoretical standard deviation over a period of time 4. Adjust the cost of the game needed to make the game fair and state your new amounts gained/lost.

OpenStudy (anonymous):

so i came up with this question

OpenStudy (anonymous):

but i am lost

OpenStudy (wolf1728):

As I said, Wikipedia has the "house advantage" (AND how to calculate it) for "Chuck A Luck" (a casino game with 3 dice). I don't know if it would complicate things but it might be worth discussing it.

OpenStudy (anonymous):

i want to make things simple, i clearly get the idea of 3 coins but i am lost in the adjustments to make it fair

OpenStudy (wolf1728):

Well at least for Chuck A Luck ypu can see the house advantage calculated (AND for 3 different winning payouts).

OpenStudy (anonymous):

brb

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