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Mathematics 19 Online
OpenStudy (anonymous):

Which function’s domain consists of all real numbers greater than 3? f(x)=3x f(x)=√x f(x)=3x+4 f(x)=1/√x-3

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

what does the domain tell us when dealing with functions?

OpenStudy (anonymous):

all possible input values?

OpenStudy (anonymous):

wait, they represent the possible output values.

OpenStudy (amistre64):

had it right the first time.. input values f(x) has a range that is dependant on x (its domain values)

OpenStudy (amistre64):

so, knowing this, how would you propose we reach a solution

OpenStudy (anonymous):

Put in values for x.

OpenStudy (amistre64):

yes, but more specifically, lets pick a value that is NOT in the domain and see if the functions hold together or not. is x=0 in the domain?

OpenStudy (anonymous):

No. ?

OpenStudy (amistre64):

if x=a is in the domain, then f(a) is defined. this has the same truth value as: if f(a) is NOT defined, then x=a is NOT in the domain. --------------------------------------------- domain is: x > 3 since 0 > 3 is false, 0 is NOT in the domain if f(0) is NOT defined, then we have determined the proper function

OpenStudy (anonymous):

Oh, okay.

OpenStudy (anonymous):

So should I plug in all x for 0 and see which one is greater than 3?

OpenStudy (amistre64):

no, you should do like i suggested put in 0 for all xs, and see which function makes no sense ... is undefined.

OpenStudy (anonymous):

That leaves all of them except for the 3rd option. Is that correct?

OpenStudy (amistre64):

correct 1/sqrt(-3) is not defined; or at least its not a defined real number.

OpenStudy (anonymous):

Thanks !

OpenStudy (amistre64):

yw

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