Which function’s domain consists of all real numbers greater than 3? f(x)=3x f(x)=√x f(x)=3x+4 f(x)=1/√x-3
@amistre64
@amistre64
what does the domain tell us when dealing with functions?
all possible input values?
wait, they represent the possible output values.
had it right the first time.. input values f(x) has a range that is dependant on x (its domain values)
so, knowing this, how would you propose we reach a solution
Put in values for x.
yes, but more specifically, lets pick a value that is NOT in the domain and see if the functions hold together or not. is x=0 in the domain?
No. ?
if x=a is in the domain, then f(a) is defined. this has the same truth value as: if f(a) is NOT defined, then x=a is NOT in the domain. --------------------------------------------- domain is: x > 3 since 0 > 3 is false, 0 is NOT in the domain if f(0) is NOT defined, then we have determined the proper function
Oh, okay.
So should I plug in all x for 0 and see which one is greater than 3?
no, you should do like i suggested put in 0 for all xs, and see which function makes no sense ... is undefined.
That leaves all of them except for the 3rd option. Is that correct?
correct 1/sqrt(-3) is not defined; or at least its not a defined real number.
Thanks !
yw
Join our real-time social learning platform and learn together with your friends!